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Electric-field strength inside a solenoid

by HeLLz aNgeL
Tags: electricfield, inside, solenoid, strength
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HeLLz aNgeL
Apr13-08, 06:38 PM
P: 30
guys, heres my question:

A long solenoid has circular cross section of radius R. The solenoid current is increasing, and as a result so is the magnetic field in the solenoid. The field strength is given by B = bt, where b is a constant.

Find an expression for the electric-field strength inside the solenoid a distance r from the axis.

Express your answer in terms of the variables B, r, R and t.

could anyone help me get started... i really have no clue on this one..

thanks !
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Dec1-09, 09:41 AM
P: 5
I actually have a question related to this.

In my case, the magnetic field is coming out of the page and there is a positively charged particle initially at rest a distance "r" from the axis of the solenoid. Then, the current in the solenoid is flipped the other way instantaneously (all of the conditions are ideal here). The problem wants me to describe the trajectory of the particle. We know the mass, m, and the charge, q, of the particle as well as the current, I, and the magnetic field, B.

As for my attempt at the solution:
I think the particle doesn't initially move because of the magnetic field because the initial velocity is zero. Perhaps the instantaneous flip of current induces some sort of electric field INSIDE the solenoid. I'm not sure about the direction (into the page, out of the page, tangential to a loop of radius r) or nature of the field, but I'm fairly certain that once it starts moving, the positive particle will be redirected by the uniform magnetic field "B" to move in a left-handed helix (of radius r?) about the solenoid axis.

Am I somewhat on the right track? There is very little info about the electric field in a solenoid so any help would be greatly appreciated. Thanks.

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