How Is the Equilibrium Formula Derived?

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Discussion Overview

The discussion centers around the derivation of the equilibrium formula in the context of general chemistry. Participants are seeking clarification on the formula's origins and its underlying principles, including the law of mass action and the relationship between forward and backward reaction rates.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant requests help in deriving the equilibrium formula, indicating a lack of personal notes.
  • Another participant suggests checking the textbook for information, implying that the derivation may be documented there.
  • A different participant notes that the equilibrium formula is not proven in their textbook, suggesting variability in educational resources.
  • One participant introduces the law of mass action, stating that at equilibrium, the rate of the forward reaction equals the rate of the backward reaction, and presents the relationship between the rate constants for both reactions.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the derivation of the equilibrium formula, with differing references to textbooks and approaches to the topic.

Contextual Notes

There are indications of missing assumptions regarding the derivation process, and the discussion reflects different educational materials and interpretations of the equilibrium concept.

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In my general chemistry class, my professor proved the equilibrium formula:

Keq = ([C]c[D]d)/([A]ab)

However, I lost my notes :frown:; hopefully someone can help derive it for me. Thanks.
 
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it's not proved in my book
 
Write Law of mass action for forward and backward rxn

At equilibrium rate of forward rxn= rate of backward rxn
And [tex]K_{eq} = \frac{k_f}{k_b}[/tex]

Where kf & kb represent the rate constant for fwd & bkw rxn
 

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