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Volume of molecule oxygen |
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| Apr16-08, 02:24 PM | #1 |
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Volume of molecule oxygen
1. The problem statement, all variables and given/known data
A mass of 0.736 kg of molecular oxygen is contained in a cylinder at a pressure of 1.0 × 105 Pa and a temperature of 1°C. What volume does the gas occupy? 2. Relevant equations PV=nRT V=nRT/P 3. The attempt at a solution n=(.736)(1000)/16 = 46 V = (46)(8.31)(274.15)/(1x10^5) where n = 46 R = 8.31 J/K/mol T = 274.15k P = 1x10^5 but that is not the correct answer, what am i doing wrong?? |
| Apr16-08, 02:32 PM | #2 |
Recognitions:
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Molecular oxygen is 0_2, two atoms of oxygen per molecule. That makes the molar mass 32g.
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| Apr16-08, 03:14 PM | #3 |
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so would i multiply the mass of .736(1000)32 to find the n, or basically i still am unsure of finding the n
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| Apr16-08, 03:18 PM | #4 |
Recognitions:
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Volume of molecule oxygen
Multiply? You divided before and that was correct. One mole of O2 has mass 32g. So how many moles is .736kg?
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| Apr16-08, 03:50 PM | #5 |
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ahh..thanks, i got it now
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