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[SOLVED] circular and projectile motion |
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| Apr24-08, 04:21 PM | #1 |
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[SOLVED] circular and projectile motion
1. The problem statement, all variables and given/known data
In the Olympic hammer throw, contestants whirl a 7.3 kg ball on the end of a 1.2 m long wire before releasing it. Suppose the hammer is released frim a height of 1.3 m while moving in a direction 24 degrees above the horizontal. If it travels 84 m horizontally, what is its radial acceleration just before release. The book answer is a = 892 m/s^2 2. Relevant equations y = x tan theta - gx^2/2v0^2 cos^2 theta a = v^2/r 3. The attempt at a solution 1.3 = 84 (.445) - 9.8 (84)^2/2v0^2 (.914)^2 v0^2 = 41386.8/36.1 = 1146.4 a = 1146.4/1.2 = 955 m/s^2 Even if I just use the velocity in the x direction, it does not work. |
| Apr24-08, 05:36 PM | #2 |
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The starting height is 1.3 m. The height when x=84 is 0 m
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