## how to find the number of excess electrons?

1. The problem statement, all variables and given/known data

How many excess electrons are on a ball with a charge of -4.00*10^-17 C?

2. Relevant equations
I know that the charge per electron is 1.60 *10^-19C.

3. The attempt at a solution

My textbook does not explain how to do this, but I thought I would divide-->4.00*10^-17 C * 1 electron/-1.60*10^-19. I got -2.5*10^-36. The answer from the book is 2.5*10^2 electrons.
I did some messing around and did this-->4.00*10^-17C*1 e/1.60*10^19C=2.5*10^2 electrons.
What's the correct way to do this problem?
 PhysOrg.com science news on PhysOrg.com >> King Richard III found in 'untidy lozenge-shaped grave'>> Google Drive sports new view and scan enhancements>> Researcher admits mistakes in stem cell study
 Recognitions: Homework Help Your set-up is right and the units will check. But how do you divide 4.0 x 10^-17 / 1.6 x 10^-19 ? What is 1 / 1.6 x 10^-19 ? (In fact, your check is also incorrect. You may want to review how division works with powers of ten and what negative exponents mean. 10^-17 / 10^-19 = 100 ; 10^-17 / 10^19 = 10^-36 .)
 uhh, i'm confused.............????

Recognitions:
Homework Help

## how to find the number of excess electrons?

You're dividing by 1.6 x .0000000000000000001 . So 4 / 1.6 is 2.5 , but what is

10^-17 / 10^-19 =

0.00000000000000001 / 0.0000000000000000001 ?
 oh i see! 10^-17/10^-19=100 so therefore 2.5*10^2. thanks so much! :D
 Charge is quantized so the excess charge has to be a multiple of e (elementary charge) q=ne, where n is the number of electrons. That's why it works I believe since your textbook didn't explain it.