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[SOLVED] Force using relativistic momentum |
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| May16-08, 07:32 PM | #1 |
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[SOLVED] Force using relativistic momentum
I have an example problem in a textbook I'm reading:
"Find the acceleration of a particle of mass m and velocity v when it is acted upon by the constant force F, where F is parallel to v. then it proceeds to show the solution: [tex]F = \frac{d}{dt}(\gamma mv) = m\frac{d}{dt}(\frac{v}{\sqrt{1-v^{2}/c^{2}}})[/tex] I get all that so far. The next step is where it loses me: [tex]= m[\frac{1}{\sqrt{1-v^{2}/c^{2}}} + \frac{v^{2}/c^{2}}{(1-v^{2}/c^{2})^{3/2}}] \frac{dv}{dt}[/tex] so I don't know how they got there... and then the next step confuses me also. They go from above to here: [tex]= \frac{ma}{(1-v^{2}/c^{2})^{3/2}}[/tex] and then of course there a few more steps after that one, but I can get those, I'm just confused about those two steps. Please help clarify it for me, thank you. |
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| May16-08, 07:38 PM | #2 |
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The first step: Use the product (or quotient) rule for taking a derivative.
The second step: Simplify. Start by getting a common denominator. |
| May16-08, 08:28 PM | #3 |
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ah, of course. I see it now. Thank you for the quick reply.
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| Nov8-09, 02:57 PM | #4 |
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[SOLVED] Force using relativistic momentum
I still can't Simplify it to the final form .. can anybody help me with that?? Thank you
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