Kinetic Energy Question

islanderman7

1. The problem statement, all variables and given/known data
A 7.0 kg bowling ball moves at 2.35 m/s. How fast must a 2.40 g Ping-Pong ball move so that the two balls have the same kinetic energy?

m1= 7.0kg
v1= 2.35m/s
m2= .0024kg
v2=?


2. Relevant equations

I know that:
KE= 1/2mv^2

3. The attempt at a solution
I set my equation like so:
KE1=KE2

and I reduced it to this:
m1v1=m2v2

I plugged in the values and solved for v2:
(7.0kg)(2.35m/s)=v2 (.0024kg)
v2= 6854.17

I put this answer in and it tells me...
wrong check mark
Your answer differs from the correct answer by orders of magnitude. m/s


What am I doing wrong? Please point me in the right direction.

Doc Al

Good.

Good.

You made an error here. The kinetic energy equation doesn't reduce to this.

(Don't leave off squaring the speeds.)

islanderman7

Thank you Doc Al.

The correct answer was 127m/s