Thermodynamics - calculate entropy

Click For Summary

Homework Help Overview

The discussion revolves around calculating the entropy of pure zinc at various temperatures, utilizing thermodynamic principles while adhering to constraints that exclude statistical definitions of entropy. Participants are exploring the implications of the third law of thermodynamics and the behavior of heat capacity at low temperatures.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss integrating the heat capacity over temperature to find entropy changes, while addressing the challenge of integrating from absolute zero due to the logarithmic singularity. There are considerations about the applicability of the third law and the potential for combining third law and standard entropies.

Discussion Status

The conversation is ongoing, with participants offering insights into the nature of heat capacity at low temperatures and referencing relevant thermodynamic models. There is no clear consensus yet, as various interpretations of the problem and potential approaches are being explored.

Contextual Notes

Participants note that the problem does not specify standard conditions and emphasizes the third law of thermodynamics. There is a mention of limitations in the provided heat capacity model at low temperatures, which may affect the calculations.

alpha_wolf
Messages
163
Reaction score
0
Hi.

I need to calculate the entropy of some material at a certain temperature given the Cp at each phase and the entalpy change and temperature at phase transitions. I'm supposed to use thermodynamic considerations (i.e. statistical definition of entropy is not applicable/allowed).

I know how to translate the entalpy change to entropy change, so I was thinking of doing an itegral of (Cp/T)dT across each of the temperature ranges, and then summing up the intergals and the entropy changes of the phase transitions. The problem is that the first integral is from 0K to the first transition temperature, so it gives ln(0) as one of the components. This is obviously not usable... I suppose this is because the polynomial definition for Cp breaks down at extremely low temperatures.

How can I overcome the problem? Maybe assume the entropy change near absolute zero is negligible and integrate from 0.1K instead of 0K? The numbers don't quite agree with that assumption...
 
Last edited:
Physics news on Phys.org
Yeah --- if you're doing third law entropies. Standard entropies give you a little wiggle room --- standard entropies of formation of elements are defined to be zero at standard conditions; compounds have non-zero entropies of formation, but they have been measured for a limited set of cases. Yours may be among them.

Third law? You've run into Einstein and Debye models for heat capacity at absolute zero? No problem integrating from zero.
 
The material in my case is pure zinc. The question doesn't state anything about standard anything, and the chapter is about the third law, so I'm assuming they want third law entropy. Perhaps there's a way to combine third law and standard entropies somehow?

Cp for the first phase is given as A + BT, where A and B are constants. An integral of Cp/T thus gives A*ln(T1) as one of the components, and when T1=0, that is a problem. I don't think we have encountered Einstein and Debye, but perhaps I just don't recognise the name of the model... Can you remind me please?
 
Third law S: 0 at 0 K. Standard state: 0 at 298 K. No combination. Hit the library for Ch. 6 in Lewis & Randall, or beat up your text index for Debye, Born and von Karman, Dewar, Einstein, Dulong & Petit (the failure at low T), Nernst.

No stat allowed? This really gets into a gray area --- D. and B. & vK. are not exactly "classical" derivations of the functional form of heat capacity at low T.
 

Similar threads

Replies
14
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K