Help Calculate Chlorine Volume @STP: 2.99x10^23 molecules

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Discussion Overview

The discussion revolves around calculating the volume occupied by 2.99 x 1023 molecules of chlorine gas at standard temperature and pressure (STP). The conversation includes various approaches and methods for performing the calculation, touching on both theoretical and practical aspects.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant requests assistance in calculating the volume of chlorine gas at STP based on a specific number of molecules.
  • Another participant suggests that all gases occupy a specific volume at STP, proposing to use the value of 22.4 liters and to multiply it by the ratio of the number of molecules to Avogadro's number.
  • A similar suggestion is reiterated, emphasizing the use of Avogadro's number (6.02 x 1023) in the calculation.
  • Another approach is presented using the Ideal Gas Law (PV = nRT), where n is calculated based on the number of molecules provided, suggesting that participants can use known values for pressure, temperature, and the gas constant to find the volume.
  • Additionally, the relationship between moles and volume at STP is highlighted, indicating that one mole corresponds to 22.4 liters, and proposing to use this ratio for the calculation.

Areas of Agreement / Disagreement

Participants present multiple methods for calculating the volume, but there is no consensus on a single approach or resolution of the calculation itself. The discussion remains open with various perspectives on how to proceed.

Contextual Notes

Some assumptions about the ideal behavior of gases and the conditions at STP are implicit in the discussion. The reliance on Avogadro's number and the Ideal Gas Law introduces dependencies that are not fully explored.

called2serve
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Can someone please calculate the volume occupied at STP by 2.99times10 to the 23rd power molecules of Chlorine. Thank you Very much.
 
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All gases have a specific size at STP. I think it's 22.4L IIRC. Just multiply 22.4 * (2.99 * 10^23) / (avogadro's number)
 
ShawnD said:
All gases have a specific size at STP. I think it's 22.4L IIRC. Just multiply 22.4 * (2.99 * 10^23) / (avogadro's number)

avogadro's number = 6.02*10^23

incase you didn't know
 
1. Use the Ideal Gas Law, PV =nRT, with n= [tex]\frac {2.99*10^{23}} {6.02*10^{23}}[/tex], to find V. You know, P, T, R, n.

OR

2. At STP, one mole of an ideal gas occupies 22.4 liters. One mole has 6.02*10^23 molecules. Use ratios to find the volume of 2.99*10^23 molecules.
 

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