How Much Energy Can a 450 m² Solar Panel Collect in an Hour?

  • Thread starter Thread starter kdrobey
  • Start date Start date
  • Tags Tags
    Maximum
Click For Summary
SUMMARY

The discussion centers on calculating the maximum energy a 450 m² solar panel can collect in one hour, given the average intensity of sunlight at 1390 W/m². The initial calculation of 625,500 W was correctly derived from the panel's area and sunlight intensity. However, the subsequent attempt to calculate energy by multiplying this power by the speed of light over time was incorrect, as it conflated power with energy units. The correct approach involves converting watt-seconds to joules to find the total energy collected.

PREREQUISITES
  • Understanding of solar panel efficiency and area calculations
  • Knowledge of power (watts) and energy (joules) conversion
  • Familiarity with basic physics equations related to energy
  • Concept of solar irradiance and its measurement
NEXT STEPS
  • Study the conversion between watts and joules to understand energy calculations
  • Research solar panel efficiency ratings and their impact on energy collection
  • Learn about solar irradiance and its variations based on geographic location
  • Explore energy storage solutions for solar energy, such as batteries
USEFUL FOR

Students in physics or engineering, renewable energy enthusiasts, and professionals involved in solar energy design and implementation will benefit from this discussion.

kdrobey
Messages
27
Reaction score
0

Homework Statement


The average intensity of sunlight at the top of the Earth's atmosphere is 1390 W/m2. What is the maximum energy that a 10 m multiplied by 45 m solar panel could collect in one hour in this sunlight?


Homework Equations


?


The Attempt at a Solution


I multiplied average density x area of the solar panel, and got 625500W that are gathered by the panel at one time. From here i did:(v of light x 3600s)x 625500w, but this just gave me an enormous number. what else can i do here?
 
Physics news on Phys.org
kdrobey said:

Homework Statement


The average intensity of sunlight at the top of the Earth's atmosphere is 1390 W/m2. What is the maximum energy that a 10 m multiplied by 45 m solar panel could collect in one hour in this sunlight?

Homework Equations


?

The Attempt at a Solution


I multiplied average density x area of the solar panel, and got 625500W that are gathered by the panel at one time. From here i did:(v of light x 3600s)x 625500w, but this just gave me an enormous number. what else can i do here?


Your big number is in units of watts and seconds. What can watt-seconds be converted to? Is that possibly some form of energy measurement?
 
I agree with your calculation of the maximum power the solar panel can receive.


kdrobey said:
1. From here i did:(v of light x 3600s)x 625500w, but this just gave me an enormous number. what else can i do here?


Am I right in thinking you multiplied this by the speed of light? If so this would make your calculation of the energy incorrect, if you included the units on the velocity it would be clear that your equation doesn't result in an energy. You were really close though...
 

Similar threads

Replies
35
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
4
Views
2K
Replies
7
Views
2K
Replies
2
Views
2K
Replies
10
Views
3K
Replies
3
Views
2K