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Total internal reflection, underwater light |
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| Aug19-08, 05:13 PM | #1 |
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Total internal reflection, underwater light
1. The problem statement, all variables and given/known data
A point source of light is at the bottom of a koi pond, at a depth of 0.525 meters. What is the radius of the circle of light formed on the water's surface? Take the index of refraction of water to be 1.33. Hint: Some of the light emitted experiences total internal reflection inside the water. 2. Relevant equations sin(crit angle) = n2/n1 n1>n2 n for air = 1.00 n for water = 1.33 3. The attempt at a solution So the critical angle for water to air is: arcsin(1/1.33) = 48.7534666 degrees This is where it all ends. There is no formula for distance or light radius. I am completely stuck at this point and cannot find anywhere in my book where I could derive the answer. I would deeply appreciate some help with this one! |
| Aug19-08, 05:34 PM | #2 |
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Draw yourself a diagram of the light source with rays emanating in all directions. For various ray angles, what happens when the light reaches the water surface? At what angle with the vertical will they be totally reflected. Use a bit of trig to figure out the radius of the circle of light.
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| Aug19-08, 05:47 PM | #3 |
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Wouldn't the radius of light only be a point at the surface if it is only a point at the bottom? I'm afraid I'm still not grasping this.
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| Aug19-08, 05:50 PM | #4 |
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Total internal reflection, underwater light
Did you draw a diagram of what's happening with the light rays?
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| Aug19-08, 05:53 PM | #5 |
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| Aug19-08, 05:53 PM | #6 |
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Yes. When the angle is not quite to the critical angle it shines out of the water. when it reaches the critical angle it shines across the surface of the water, but none shines into the air, and when it is past the critical angle no light shines out of the water only deeper back into the water.
I think I see why it stays in the water and all that, but I fail to see how there is a radius of light at the surface, when it is only a point form the source. Sorry if I am being rather thick. |
| Aug19-08, 06:00 PM | #7 |
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Ooooooooooooooooh. I got it now. Thank you so much.
The light was shining a cone straight up, but past 48 degrees it was reflecting back into the water. I was thinking it was a laser beam aimed at 48 degrees. Thanks again! I got the right answer |
| Aug19-08, 06:01 PM | #8 |
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| Aug19-08, 06:03 PM | #10 |
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That last little bit really clarified what I was looking for. Thanks for the help Doc Al. Guess I'll try and get cracking on another stumper.
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