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Resolved shear stress(rss) problem 
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#1
Aug3008, 09:49 AM

P: 14

Can anyone tell me how to find the angle between tensile force and slip direction under these conditions:
1. Tensile force is applied along [010] direction for a single crystal of iron(BCC). 2. rss is directed along (110) plane and in a [111] direction when tensile stress of 52 MPa is applied. thank you 


#2
Oct1010, 05:20 PM

P: 2

I am not sure enough but this is my solution:
Suppose lambda is your angle: tan(lambda)=a*sqrt(2)/a=sqrt(2) lambda=tan^1(sqrt(2)) 


#3
Oct2010, 02:48 AM

P: 3

The schmid law allows you to calculate the shear stress as a function of the tensile stress :
rss=sigma.cos(phi).cos(lambda) where phi is the angle between the tensile direction and the slip plane normal ([110] in your case) and lambda is the angle between the tensile direction and the slip direction ([111] in you case). To find cos(phi) and cos(lambda) you can use the scalar product : 1*0+1*1+1*0=sqrt(2)*sqrt(1)*cos(phi) ==> cos(phi)=1/sqrt(2) 1*0+1*1*1*0=sqrt(3)*sqrt(1)*cos(lambda) ==> cos(lambda)=1/sqrt(3) Then: rss=52*1/sqrt(2)*1/sqrt(3) 


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