Solve Calculus Problems: Limits and Gradients Explained | Algebra II Tips

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Homework Help Overview

The discussion revolves around evaluating limits and finding gradients in calculus, specifically focusing on a limit problem involving a rational function and a question about the derivative of an exponential function.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to evaluate a limit involving a rational function and expresses uncertainty about factoring the denominator. They also seek clarification on finding the gradient of an exponential function.
  • Some participants provide feedback on the factoring of the denominator and suggest corrections to the original poster's approach.
  • Another participant offers a formula for the derivative of an exponential function, noting the terminology difference between "gradient" and "derivative."

Discussion Status

The discussion includes attempts to clarify the limit evaluation and the derivative of an exponential function. Participants are exploring different interpretations and providing guidance without reaching a consensus on the limit's evaluation.

Contextual Notes

The original poster mentions confusion regarding factoring cubes and the terminology used in calculus, indicating a potential gap in foundational knowledge that is being addressed through the discussion.

Sombra
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Ok, I have 2 problems. I think my first one deals with an algebra II thing. But, it's: Evaluate the limit (if it exists):

lim (x approaches -2) (x+2)/(x^3 +8)

I think my problem came from factoring the denominator, which I got as
(x+2)(x^2 - 4x +2), so my answer came out to be 1/14, which is not one of the answer choices. I can't remember factoring cubes. I know it's SOPSMS, but I can't even remember how to do that.

My other problem. Can anyone give me an example of finding the gradient of a function at, say x=3, for something that has an exponent with a variable? Maybe 4^x. Thanks!
 
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You cube is almost correct but you needed to multiply 2 and x and have 2^2 at the end so you should get (x+2)(x^2 - 2x +4). The answer is 1/12
 
Sombra said:
My other problem. Can anyone give me an example of finding the gradient of a function at, say x=3, for something that has an exponent with a variable? Maybe 4^x. Thanks!

I assume you want, for example:
[tex]\frac{d}{dx} 4^x=\ln 4 \times 4^x[/tex]

(It's usually called a derivative in english. Gradient refers to other things.)
 
In a bit more detail: if y= ax, then ln(y)= x ln(a) so (ln(y))'= (1/y)y'= ln(a)
Then y'= ln(a) y= ln(a) ax.
 

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