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Compton scattering elastic? 
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#1
Sep1408, 01:36 PM

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In the usual calculaltion of the Compton effect we assume an elastic collision between a photon and an electron. Energy and momentum of the particles are conserved before and after the collision.
In fact, the electron is subject to a high acceleration during the collision, and classically it should therefore radiate. Is this accounted for in the usual treatment of the subject? Or should there be a correction of some kind for radiative losses? 


#2
Sep1408, 03:46 PM

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The collision itself is elastic. Anything that happens afterwards (radiation losses) is irrelevant.



#3
Sep1408, 04:09 PM

P: 72




#4
Sep1408, 08:06 PM

P: 2,051

Compton scattering elastic?
In this case ("collision" with a "photon" of all things) it seems like folly to factor in classical radiative losses. Either consider a completely classical treatment (in which, you will find, what you considered the "scattered photon" really is the radiation due to an acceleration of the particle, albeit the transverse acceleration, and the corresponding radiative losses are crucial to the mechanism of the longitudinal acceleration) or a completely quantum treatment (sure, the acceleration may be high, but the time period is small). 


#5
Sep1508, 09:13 AM

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P: 1,261

Applying classical effects to a quantum process leads to confusion.
The emission of one or more additional photons in the collision (making it inelastic) can be, and has to be, treated in QED. 


#6
Sep1608, 07:33 PM

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P: 1,082

Marty  Great question. You are absolutely right that the electron radiates because of its acceleration. For many scattering experiments, the socalled radiative corrections are important  they come from Feynman diagrams in which the scattering charged particles emit photons. For example, one process involves 1. emit a photon, then 2. absorb the incoming photon, and 3. emit the final Compton photon.
The computations are tricky, they involve the specific experimental detection setup, and both infrared and ultraviolet divergences  the first solved by Bloch and Nordseick, the second by Schwinger. The basic idea is to subtract out the effects of the acceleration induced radiation; the topic is called radiative corrections. Strictly speaking, there is no such thing as elastic scattering of charged particles. However, there are plenty of circumstances for which the scattering is elastic to a very good approximation. My dissertation dealt with radiative corrections to various electronnucleon scattering experiments  which experiments helped explore the electromagnetic structure of protons and neutrons in the early 1960s. A very exciting time it was. Regards, Reilly Atkinson 


#7
Sep1908, 07:53 AM

P: 72

Wouldn't the radiated energy be much less than a single quantum, because the electron doesn't go through even a single cycle of oscillation? How do we reconcile this with the quantization of radiation?



#8
Sep1908, 06:30 PM

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The radiated photon can have any momentum, and associated energy, subject to conservation of total momentum and energy. Regards, Reilly Atkinson 


#9
Sep1908, 07:20 PM

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#10
Sep2108, 08:11 PM

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P: 1,082

Photons have energy hw, with w the frequency. This holds for all frequencies from 0 to infinity. Write down the conservation of energy and momentum equations for, say,
electron + photon > electron + photon + photon to see how things balance. The actual restriction of the radiating photon energies are due to the properties of the detection apparatus. Typically, one detects over a small area or volume, which means that an electron that radiated a little bit can be detected as well as one that does not radiate. Radiative corrections simply factor out the contribution of radiation for the detection scheme used.. Regards, Reilly Atkinson 


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