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Discrete Mathematics |
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| Sep17-08, 04:01 PM | #1 |
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Discrete Mathematics
I know I have to write an equation to solve the problem down. But I realy don't know how to use the given information. I did it by enumeration, but I don't get it how this will be shown by an algebriac argument. Please some one help me at least with an idea.
If S = {1,2,3,4}, consider the function f:SxS-> N defined by f(x,y)= 4x+y-4. Determine the image of f, and show by an algebraic argument [not by enumeration] that f is one to one function on SxS. [hint: because S has only four elements, the difference of two of its elements is a multiple of 4 iff they are equal.] |
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| Sep17-08, 04:31 PM | #2 |
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Recognitions:
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f(x1,y1)-f(x2,y2)=4(x1-x2)+(y1-y2). This can be 0 if and only if x1=x2 and y1=y2.
4(x1-x2) is ALWAYS a multiple of 4, while (y1-y2) cannot be a multiple of 4 unless y1=y2. |
| Sep18-08, 06:53 AM | #3 |
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Thank you so much. I get it now.
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