
#1
Sep3008, 12:28 PM

P: 53

1. The problem statement, all variables and given/known data
A relief airplane is delivering a food package to a group of people stranded on a very small island. The island is too small for the plane to land on, and the only way to deliver the package is by dropping it. The airplane flies horizontally with constant speed of 290 mph at an altitude of 850 m. For all parts, assume that the "island" refers to the point at a distance D from the point at which the package is released, as shown in the figure. Ignore the height of this point above sea level. Assume that the acceleration due to gravity is g = 9.80 m/s^2. a) After a package is ejected from the plane, how long will it take for it to reach sea level from the time it is ejected? Assume that the package, like the plane, has an initial velocity of 290 mph in the horizontal direction. b)If the package is to land right on the island, at what horizontal distance D from the plane to the island should the package be released? c)What is the speed v_f of the package when it hits the ground in mph Equations x1=x0 + v0x(t1t0) y1= y0 + v0y(t1t0) 0.5(g)(t1t0)^2 3. The attempt at a solution a)13.1s b)1710m c) I am not sure how to do c. At first i thought speed would be 0 when it hits the ground, but i am told that is incorrect 



#2
Sep3008, 02:35 PM

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Hint: v_{f}² = v_{horizontal}² + v_{vertical}² 



#3
Sep3008, 02:47 PM

P: 53

vf² = vhorizontal² + vvertical²
Does that mean Vf^2 = 290mph^2 +0mph^2 Vf = Square root of (290^2) Vf=290mph 



#4
Sep3008, 02:53 PM

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Delivering a package by airuse the usual formula to find v_{vertical} 13.1s later. 



#5
Sep3008, 03:06 PM

P: 53

So does that mean:
Vfy=Viyg(Delta t) Vfy=04.38(13.1) ***9.8m/s = 4.38mph Vfy=751.65mph Vfx=0mph Therefore, Vf = 751.65 Is that right? 



#6
Sep3008, 03:14 PM

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Vfy=Viyg(∆t) is right. But your g is wrong. g is not 9.8m/s … it's 9.8m/s² … you need to convert it to miles/s². 



#7
Sep3008, 03:33 PM

P: 53

So does that mean:
9.8m/s^2 = 0.006 089 mile/s^2 Vfy=290mph0.006089mile/s^2(13.1s) Vfy=290mph0.7976m/s Vfy=290mph1.178mph =288.8mph 



#8
Sep3008, 03:46 PM

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ii] it's 0.07976m/s iii] where did 1.178 come from? 



#9
Sep3008, 03:58 PM

P: 53

OOPs
Vfy=290mph0.006089mile/s^2(13.1s) Vfy=290mph0.7976mile/s Vfy=290mph2871.36mph =? That doesnt make any sense. Am I converting it wrong 


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