
#1
Oct808, 03:53 AM

P: 3

1. The problem statement, all variables and given/known data
Q1: A car accelerates uniformly from rest to a speed of 79.7 mi/h in 9.01 s. Find the constant acceleration (expressed in m/s2) of the car. Answer in units of m/s2. Q2: Find the distance (expressed in m) that the car travels during this time. Answer in units of m. 2. Relevant equations Acceleration Distance 3. The attempt at a solution Q1: 79.7mi/h = 35.6m/s 35.6/9.01 = 3.95m/s2 Q2: 3.95/2 * 9.01 = 17.79m 



#2
Oct808, 03:56 AM

P: 328

Q1 looks fine to me, Q2 though, what formulae did you use?
I would have used [tex] s = ut + \frac{1}{2} at^2 [/tex] where s = displacement u = initial velocity t = time a = acceleration This is the same as what you've done except your t is not squared. 


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