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Constant Acceleration Distance

by Masq
Tags: acceleration, distance
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Masq
#1
Oct8-08, 03:53 AM
P: 3
1. The problem statement, all variables and given/known data
Q1: A car accelerates uniformly from rest to a
speed of 79.7 mi/h in 9.01 s.
Find the constant acceleration (expressed
in m/s2) of the car. Answer in units of m/s2.


Q2: Find the distance (expressed in m) that the
car travels during this time. Answer in units
of m.

2. Relevant equations
Acceleration
Distance



3. The attempt at a solution
Q1:
79.7mi/h = 35.6m/s
35.6/9.01 = 3.95m/s2

Q2:
3.95/2 * 9.01 = 17.79m
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Rake-MC
#2
Oct8-08, 03:56 AM
P: 328
Q1 looks fine to me, Q2 though, what formulae did you use?

I would have used [tex] s = ut + \frac{1}{2} at^2 [/tex]

where s = displacement
u = initial velocity
t = time
a = acceleration

This is the same as what you've done except your t is not squared.


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