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Gravitational attraction between 3 masses. 
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#1
Nov208, 06:23 PM

P: 5

1. The problem statement, all variables and given/known data
A small mass M and a small mass 3M are 3.60m apart. Where should you put a third small mass so that the net gravitational force on it due to the other two masses is zero?(From mass M) 2. Relevant equations F = G(m1)(m2)/d^2 3. The attempt at a solution
x = Distance between [1M] and (1M) 3.60x = distance between (1M) and [3m] I was thinking this would give me an equation looking like this: G[1M](1M)/x^2 = G(1M)[3M]/(3.60x)^2 I tried solving this but it's not giving me the right answer... Should the right equation above be G(2M)(3M)/(3.60x)^2 because of combined mass? 


#2
Nov208, 06:45 PM

Mentor
P: 15,170

You claimed the quoted equation is "not giving me the right answer." That implies that either you know what the right answer should be or that some agent knows your result is wrong. Show your work. 


#3
Nov208, 06:50 PM

P: 5

ahh never mind, i see.
It turns out i just suck at math. that equation gave me 1.32 which was the right answer. thanks for the help 


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