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logarithms! |
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| Nov19-08, 05:29 PM | #1 |
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logarithms!
1. The problem statement, all variables and given/known data
12^x=4X8^(2x) Big X= multiplication sign little x= unknown i simply cannot figure this out. Any help please? 2. Relevant equations 4.6X1.06^(2x+3)=5X3^(x) |
| Nov19-08, 05:40 PM | #2 |
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Use logarithms! Isn't that your title? Take the log of both sides and use the rules of logarithms to simplify. What do you get?
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| Nov19-08, 05:56 PM | #3 |
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| Nov19-08, 06:01 PM | #4 |
Recognitions:
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logarithms!
log(12^x)=log(4*8^(2x)). That wasn't so hard. Now simplify it. Use rules of logarithms like, log(a*b)=log(a)+log(b), log(a^b)=b*log(a).
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| Nov19-08, 06:06 PM | #5 |
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Your equation is 12[sup]x=(4)8[sup]2x[sup].
Since you titled this "logarithms", Dick assumed you knew some basic rules of logarithms. Take the logarithm of both sides: log(12x= log((4)8[sup]2x[sup]) Now use the fact that log(ab)= log(a)+ log(b) and that log(ax)= x log(a). |
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