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Logarithms!by moe11
Tags: logarithms 
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#1
Nov1908, 05:29 PM

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1. The problem statement, all variables and given/known data
12^x=4X8^(2x) Big X= multiplication sign little x= unknown i simply cannot figure this out. Any help please? 2. Relevant equations 4.6X1.06^(2x+3)=5X3^(x) 


#2
Nov1908, 05:40 PM

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Use logarithms! Isn't that your title? Take the log of both sides and use the rules of logarithms to simplify. What do you get?



#3
Nov1908, 05:56 PM

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#4
Nov1908, 06:01 PM

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Logarithms!
log(12^x)=log(4*8^(2x)). That wasn't so hard. Now simplify it. Use rules of logarithms like, log(a*b)=log(a)+log(b), log(a^b)=b*log(a).



#5
Nov1908, 06:06 PM

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Your equation is 12[sup]x=(4)8[sup]2x[sup].
Since you titled this "logarithms", Dick assumed you knew some basic rules of logarithms. Take the logarithm of both sides: log(12^{x}= log((4)8[sup]2x[sup]) Now use the fact that log(ab)= log(a)+ log(b) and that log(a^{x})= x log(a). 


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