Four IQ test problems

~~leopard~~ · Nov21-08, 05:16 PM

**Werg22** · Nov22-08, 02:06 AM

Spoiler

1. 2

The 2nd square in a row shares all of the 3rd square's lines, not accounting for translation. This leaves 2 as the only choice.

2. 5

This is about having the same number of black squares inside a square and outside. Their numbers are already the same, which means the answer is 5.

The other 2 are obvious...

~~leopard~~ · Nov22-08, 05:31 PM

2 and 4?

**davee123** · Nov22-08, 06:27 PM

The only one I haven't gotten so far is the 1st one...

Originally Posted by Werg22

Spoiler

The 2nd square in a row shares all of the 3rd square's lines, not accounting for translation. This leaves 2 as the only choice.

Spoiler

I dunno if I like that reasoning since it would appear to ignore the 1st square in each row, making the 1st square's content arbitrary. In other words, you could place an irregular pentagon circumscribed by an oval into any square in the 1st column, and your solution would appear to be unaffected.

I don't like my answer (as it's sort of similar), but here's what I've come up with:

The number of distinct white regions in each square is:
4 2 1
8 4 2
3 2 ?
Now, this means from the top row to the middle row, each of the numbers of white regions double. And from the middle to the bottom row, they're log(root 2)'d. So the number of white regions in a given column corresponds to: A, 2*A, log base 2(2*A). Hence, the only viable option is choice #1, because it's the only one with a single white region.

DaveE

**ƒ(x)** · Nov28-08, 09:21 PM

Please correct me if one or more of my answers are wrong. I am not completely sure about 1 and 3.

Problem 1:

Spoiler

I believe that the answer is 5.

Problem 2:

Spoiler

The correct answer is 5. Assign each of the squares inside the box a value of -1 and each of the outside ones a value of +1. The rest should be easy

Problem 3:

Spoiler

I believe that the answer is 2. One reason would be symmetry. 1, 3, and 5 would work because each of them would cause for there to be an equal number of white and red squares, but then it would not be symmetrical.

Problem 4:

Spoiler

I think that the correct answer is 4. Each of the shapes shifts one unit to the right and wraps around to the next line. With the exception of the circles, the shapes cycle through the colors blue, red, and green. In that order. So the next triangle is green. There is a second way to look at this, rather than looking that rows one looks at diagonals. Each way leads to the same answer though.

**davee123** · Nov29-08, 01:12 AM

Originally Posted by ƒ(x)

Problem 1:

Spoiler

I believe that the answer is 5.

I'm still curious about this problem-- any reason why?

DaveE

**maze** · Nov29-08, 03:28 AM

Originally Posted by ƒ(x)

Please correct me if one or more of my answers are wrong. I am not completely sure about 1 and 3.

Problem 3:

Spoiler

I believe that the answer is 2. One reason would be symmetry. 1, 3, and 5 would work because each of them would cause for there to be an equal number of white and red squares, but then it would not be symmetrical.

I'm pretty sure thats right, but not for the reason you give

Spoiler

Imagine the shape folded into a cube. 2 would have the cube cleanly divided half and half into red and white parts.

**ƒ(x)** · Nov29-08, 04:34 PM

Originally Posted by davee123

I'm still curious about this problem-- any reason why?

DaveE

Let me think....I remember that I went off on some tangent...

Hm...

**ƒ(x)** · Nov29-08, 04:35 PM

Does anyone happen to know what the correct answers are?

**ninjaDUDE** · Jan12-09, 10:03 PM

pretty simple:

Spoiler

1. 2
2. 5
3. 2
4. 4

**sahajumang** · Jan19-09, 02:52 PM

Am sure about 3 and 4, they are pretty simple but dunno about 1, 2.

3- 2nd
4-4th

**moe darklight** · Jan19-09, 03:37 PM

2 3 4 I thought were pretty obvious.

#1 is kicking my *** though. I call defeat.

here's looking at me, kid:
FAIL

**Soca fo so** · Feb26-09, 12:12 PM

I got:

Spoiler

1. 3

number of straight lines equals number of curved lines

2. 5 or 4

5 with the rule number of black squares inside equals number outside

or 4 with the rule number of squares increases by 2 for each row/column starting from the top/left

3. 2

4. 4

**davee123** · Feb26-09, 02:47 PM

Originally Posted by Soca fo so

Spoiler

1. 3

number of straight lines equals number of curved lines

What exactly do you mean? Counting curved line segments, I get:

Code:

2 1 4         4  1 10
4 2 0   OR:  10  2  0
2 1 ?         2  1  ?

And counting straight line segments, I get:

Code:

0 1 1         0  2  3
0 4 4   OR:   0  8  4
1 2 ?         3  4  ?

How do the numbers of curved vs. straights relate?

[edit]

Spoiler

I did just notice an interesting pattern with the number of intersections, though. The number of curved line segments in each square is equal to the number of line *intersections* (not corners). Which would similarly make the answer #3. Huh. I like that answer, actually.

DaveE

**Soca fo so** · Feb26-09, 04:12 PM

Sorry yeah I should have been more explicit, I meant:

Spoiler

The totals when you add all 9 boxes together, and that e.g the two circles in the first box would be counted as two curved lines.

I think I prefer your explanation for why it would be 3 better though. I'm not sure I really like the answer to the second question being 5 either.

EDIT

Spoiler

In answer four would the touch of thecircle and oval count as an intersection and would the touch be considered a double touch/intersection?

**davee123** · Feb27-09, 01:21 PM

Originally Posted by Soca fo so

In answer four would the touch of thecircle and oval count as an intersection and would the touch be considered a double touch/intersection

It either counts as 1 intersection or 0 intersections, I would think-- each of which wouldn't fit as an answer. It would only count as 2 if the two ovals intersected, similarly to the upper-left corner of the problem.

DaveE