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gauss law in gravitation |
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| Dec1-08, 11:56 PM | #1 |
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gauss law in gravitation
Can gauss law in its equivalent form be used to determine the gravitational field??
If so how?? |
| Dec2-08, 12:16 AM | #2 |
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Yes. Notice how gravity corresponds with electrostatics; for point masses/charges you have
[tex]\vec E = \frac{1}{4\pi\epsilon_0} \frac{q}{r^2} \hat r \leftrightarrow \vec g = -G \frac{m}{r^2} \hat r.[/tex] Thus you have the correspondences [tex]q \leftrightarrow m, 1/4\pi\epsilon_0 \leftrightarrow -G[/tex]. From Gauss's law (in integral form) for electrostatics, you can get the corresponding equation for gravity: [tex] \oint \vec E \cdot d \vec a = \frac{q_{encl}}{\epsilon_0} \leftrightarrow \oint \vec g \cdot d \vec a = -4\pi Gm_{encl}. [/tex] In differential form you get [tex] \nabla \cdot \vec E = \frac{\rho_e}{\epsilon_0} \leftrightarrow \nabla \cdot \vec g = -4\pi G \rho_m [/tex] where [tex]\rho_e[/tex] is the charge density, and [tex]\rho_m[/tex] is the mass density. |
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