Electric Field at Surface & Inside Thin Hollow Sphere

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Homework Help Overview

The discussion revolves around the electric field generated by a thin hollow sphere with a uniform surface charge density, particularly focusing on the electric field at the surface and within a drilled hole in the sphere.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of Gauss' Law and symmetry to determine the electric field at the surface. There is also consideration of superposition principles for the scenario involving a hole in the sphere.

Discussion Status

Some participants have provided insights into the electric field calculations at the surface and have begun discussing the implications of introducing a hole. There is an ongoing exploration of different perspectives and methods to approach part b of the problem.

Contextual Notes

Participants are navigating the complexities of electric fields in relation to surface charge distributions and the effects of modifying the charge configuration by drilling a hole. There may be assumptions regarding the uniformity of charge distribution and the negligible impact of the hole on the overall charge density.

PinkFlamingo
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I'm also stuck on this one. Could someone help me please? :confused:

An insulating, thin, hollow sphere has a uniform surface charge density, a.

a) show that the magnitude of the electric field at the surface of the sphere is |a|/E0 (where E0 is the permittivity of free space)

b) a tiny hole is drilled through the shell, thus removing a negligible but of the charge. Show that the magnitude of the electric field in this hole is |a|/2E0
 
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For part a, consider that the surface of the Earth "looks" flat to us. Alternatively, you can use Gauss' Law and symmetry.

I'd have to think about b for a little bit. I'll leave that to one of the regular helpers here.
 
For Part b: The original sphere with a hole in it can be viewed as a superposition of the sphere with charge density a and the "hole" (i. e. a little piece of the surface) with charge density -a . So what you do is you compute the fields of the two charge distributions separately and then add them up. The field of the sphere you've computed already (zero inside!), and the field of a surface charge is...
 
If the point is sufficiently close to the surface of the sphere, then even the "little piece of surface" that kueng described looks like an infinite sheet of charge to that point...and the field from an infinite sheet of charge is...
 

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