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Equivalence of Boltzmann and Clausius entropy

 
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Dec4-08, 08:03 PM   #1
 

Equivalence of Boltzmann and Clausius entropy


I can't figure out how to show that the Clausius entropy

[tex] \Delta S= \int_{T_1}^{T_2} \frac{dQ}{T}[/tex]

is equivalent to the Boltzmann entropy

[tex] S=kln \Omega [/tex]

at thermal equilibrium.

Does anyone know how to do this?
 
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Dec7-08, 04:54 AM   #2
 
bump
 
Dec7-08, 06:30 AM   #3
 
Might want to see how it works for monoatomic ideal gas first, then look for a generalization.
 
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