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Equivalence of Boltzmann and Clausius entropy 
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#1
Dec408, 08:03 PM

P: 144

I can't figure out how to show that the Clausius entropy
[tex] \Delta S= \int_{T_1}^{T_2} \frac{dQ}{T}[/tex] is equivalent to the Boltzmann entropy [tex] S=kln \Omega [/tex] at thermal equilibrium. Does anyone know how to do this? 


#2
Dec708, 06:30 AM

P: 504

Might want to see how it works for monoatomic ideal gas first, then look for a generalization.



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