
#1
Dec608, 07:41 PM

P: 2

1. The problem statement, all variables and given/known data
evaluate if and S is the surface of the region in the first octant bounded by x = 0, y = 0, below by z = 1, and above by 2. Relevant equations 3. The attempt at a solution I used the divergence of F=5y+4z+7x. My integral was int(theta from 0 to pi/2)int(r from 0 to 2)int(z from 1 to 4r^2) (5r^2sin(theta)+4rz+7r^2cos(theta)) dzdrdtheta. I get 26pi/3+96/5, but that's not the right answer. Is my setup wrong or am I evaluating it wrong? 



#2
Dec708, 07:58 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,882

You set up is correct. I haven't checked the evaluation of the integral.




#3
Dec708, 12:03 PM

P: 2

Thanks for the help, but I figured it out and my setup wasn't correct. At z=1 which is the base of the region, r goes to sqrt(3) not 2. So the r integral goes from 0 to sqrt(3).



Register to reply 
Related Discussions  
Divergence theorem  Advanced Physics Homework  3  
Divergence Theorem  Calculus & Beyond Homework  2  
*screams in anger* ok, divergence theorem problem  Calculus & Beyond Homework  8  
divergence theorem...again  Introductory Physics Homework  2  
Problem with the Divergence Theorem  General Math  7 