|Dec6-08, 09:31 PM||#1|
calculating angular speed out of tangential speed
1. The problem statement, all variables and given/known data
A particle A is moving at constant tangential speed v1 = 2m/s on a circumference of radius r1 = 5m.
Particle B is performing a uniform circular motion on a circumference whose radius is r2 = (2)r1.
Find the tangential speed of v2 of particle B assuming that the angular speed w2 of particle B is twice the angular speed w1 of particle A
2. Relevant equations
Tangential speed at 10m from the axis point is 2 times the tangential speed at 5m from the axis.
3. The attempt at a solution
v1=2m/s at 5m from the axis of rotation
IF particle B was rotating at the same angular speed....v2=4m/s
BUT w2 = 2w1 SO v2=8m/s
|Dec6-08, 09:52 PM||#2|
That looks correct.
v/r = 2/5 = ω
2ω = 4/5
v = ω *r = 4/5*10 = 8
|angular momentum, rotation about axis, tangential|
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