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calculating angular speed out of tangential speed |
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| Dec6-08, 09:31 PM | #1 |
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calculating angular speed out of tangential speed
1. The problem statement, all variables and given/known data
A particle A is moving at constant tangential speed v1 = 2m/s on a circumference of radius r1 = 5m. Particle B is performing a uniform circular motion on a circumference whose radius is r2 = (2)r1. Find the tangential speed of v2 of particle B assuming that the angular speed w2 of particle B is twice the angular speed w1 of particle A 2. Relevant equations Tangential speed at 10m from the axis point is 2 times the tangential speed at 5m from the axis. 3. The attempt at a solution v1=2m/s at 5m from the axis of rotation IF particle B was rotating at the same angular speed....v2=4m/s BUT w2 = 2w1 SO v2=8m/s |
| Dec6-08, 09:52 PM | #2 |
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Recognitions:
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That looks correct.
v/r = 2/5 = ω 2ω = 4/5 v = ω *r = 4/5*10 = 8 |
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| angular momentum, rotation about axis, tangential |
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