
#1
Dec1308, 02:56 AM

P: 110

Not a homework problem but pretty basic for you guys so I figure it belongs here
Two problems Q1 If I throw a steel ball (inelastic) at a wall at an angle of 45d how do I calculate the resultant force on the wall. Q2 Extending question 1 I throw a steel ball at two steel plates welded together at 90 degrees. The ball hits one wall of the structure bounces off into the other wall and back to the original wall and then out again How would I calculate the individual forces on the structure and then SUM them to calculate the overall resultant force on the structure. I know this is a little unclear so I have included diagrams to show what I am looking for you may need to wait till the diagram is approved to see what I am looking for. The problems seem fairly straightforward but my searches did not turn up a hit for the maths involved. I am probably not searching using the right criteria. My apologies in advance if this question has been answered multiple times before. CC 



#2
Dec1308, 03:32 AM

P: 8





#3
Dec1308, 07:27 PM

P: 110

Thanks jscushman. I am not sure what you mean by "brought to a (horizontal) stop" I think you mean all the energy was absorbed by the wall, is that correct? In the case above the ball bounces off the wall at its incident angle of 45 degrees, So I don't think your formula would apply would it? Or did you mean something else?
I found a very good and basic source of information, great for someone who has long forgotten his vector maths as I obviously have, hopefully it will help someone else http://www.glenbrook.k12.il.us/gbssc...ors/u3l1a.html I still have a question but I am not sure it can be answered so I am continuing to look. that is how do I calculate how much momentum is lost when the steel ball hits the wall. I figure that will need to include material composition elasticity friction and probably gravity as well So if anyone knows a good resource for that type of information it would be great. once I have the basic vector math I can then move to the next step in my problem modeling real world action. CC 



#4
Dec1308, 09:54 PM

P: 8

vectors and resultant forcesAssume that the ball is initially headed towards the wall with a speed v at an angle of 45˚. When it bounces off the wall, it will also be an an angle of 45˚. (Assuming that) the wall is vertical, and it can only provide a force normal to its surface, it can only change the horizontal velocity of the ball. In this case, the initial horizontal velocity is v/√(2) (which is from v cos 45˚), and the final horizontal velocity is v/√(2), so the change in momentum (the mass times the change in velocity) is 2mv/√(2)=√(2) mv. The impulse is equal to the change in momentum. To find the force that the ball applied to the wall you need to divide this impulse by the amount of time the ball was in contact with the wall. 



#5
Dec1308, 09:57 PM

P: 8




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