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Error terms in Taylor Series |
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| Dec16-08, 02:43 PM | #1 |
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Error terms in Taylor Series
It is known that
[tex] \sum\limits_{k = 0}^\infty {\frac{{N^k }}{{k!}}} = e^N[/tex] I am looking for any asymptotic approximation which gives [tex] \sum\limits_{k = 0}^M {\frac{{N^k }}{{k!}}} = ? [/tex] where [tex]M\leq N[/tex] an integer. This is not an homework |
| Dec16-08, 09:18 PM | #2 |
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I'm only being a little facetious if I point out that the sum is asymptotically equal to e^N.
Want more accuracy? It's better approximated by e^N-[x^(N+1)]/(N+1)! |
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