# An airplane flying with a velocity...

Tags: airplane, flying, velocity
 P: 24 [b]1. The problem statement, all variables and given/known data An airplane is flying with a velocity of 85.0 m/s at an angle of 19.0 degrees above the horizontal. When the plane is a distance 106 m directly above a dog that is standing on level ground, a suitcase drops out of the luggage compartment. [b]2. Relevant equations How far from the dog will the suitcase land? You can ignore air resistance. [b]3. The attempt at a solution I attempted to use Y-Yinitial = Voy(t) - 1/2(g)(t^2) I solved for t and i got t = 4.651 s. That answer was incorrect. I then tried using Vx = (85m/s)(cos19) = 80.37 Vy = (85m/s)(sin19) = 27.67 I then tried adding them using V = sqrt{(80.1^2) - (27.7^2)} = 75.16 m/s I then did R = Vox(t) but the answer I got wasn't correct. Help!
 HW Helper P: 5,346 Welcome to PF. The problem is that the vertical velocity continues to carry it upward before it goes down. What if you reduced the problem to throwing a ball straight up at 27 m/s and you are standing on a 105m cliff? Find that time and multiply by the horizontal velocity.
 P: 24 I'm still not sure how to solve this =(
HW Helper
P: 5,346

## An airplane flying with a velocity...

 I attempted to use Y-Yinitial = Voy(t) - 1/2(g)(t^2) I solved for t and i got t = 4.651 s.
You have the right method.

 P: 24 Ohh! I didn't realize my mistake. I used 0 for Voy instead of 85m/s which is the initial velocity. I solved the quadratic using the positive value and I got 1.168s. I then multiplied that by 85m/s to find the range and I got 99.28m. Does that sound correct?
HW Helper
P: 5,346
 Quote by spacecadette Ohh! I didn't realize my mistake. I used 0 for Voy instead of 85m/s which is the initial velocity. I solved the quadratic using the positive value and I got 1.168s. I then multiplied that by 85m/s to find the range and I got 99.28m. Does that sound correct?
No.

Besides your quadratic should yield t to hit the ground. It can't get to the ground in 1 sec from 100 m.
 P: 24 I'm sorry, I'm confused again.
HW Helper
P: 5,346
 Quote by spacecadette I'm sorry, I'm confused again.
Write out the equation for your quadratic. Let's see where you are going wrong.
 P: 24 -85 (+ or -) sqrt{(-85^2) - 4(4.9)(-106) all divided by 2(4.9) I think that when I added the -85 to the problem I ended up with 1.168 Now when I subtracted the -85 to the problem I got 18.51s. Which seems more realistic.
HW Helper
P: 5,346
 Quote by spacecadette -85 (+ or -) sqrt{(-85^2) - 4(4.9)(-106) all divided by 2(4.9) I think that when I added the -85 to the problem I ended up with 1.168 Now when I subtracted the -85 to the problem I got 18.51s. Which seems more realistic.
But 85 is the velocity of the plane and it is not going straight up.

Your vertical component of velocity is 85*Sin19° = 27.67

That should yield 0 = 105 + 27.67*t -4.9*t2

I use this on-line calculator btw:
 P: 24 Ohhh I understand now. Thank you so much for your help!
 P: 24 How far from the dog will the suitcase land? I'm still having issues finding the distance.
HW Helper
P: 5,346
 Quote by spacecadette How far from the dog will the suitcase land? I'm still having issues finding the distance.
That's the easy part now.

You have time to hit the ground.
You have the horizontal velocity projected along the ground ...

Speed * time = distance.

 Related Discussions Introductory Physics Homework 1 Introductory Physics Homework 4 Introductory Physics Homework 8 Introductory Physics Homework 2 Introductory Physics Homework 5