Need help on easy questions from phy 105

[links0311]

what is the equation for a period on a pendulum? and what is the answer to this:

Two waves of equal amplitude and wavelength of .8m travel in a string in opposite directions with speeds of 250 m/s. if the string is 2.0 meters long, how many segments of standing waves are set up in the string?

whats the answer and please give a short explanation.
I need an answer in the next 15 minutes, i need a miracle!

beau

 

[Blistering Peanut]

Simple Pendulum: $$T = 2 \pi \surd({l \over g})$$

 

[M98Ranger]

Hi Beau,

I'm happy to help with your questions from PHY 105. The equation for the period of a pendulum is T=2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

As for the second question, we can use the formula v=fλ to find the frequency of the waves, where v is the speed, f is the frequency, and λ is the wavelength. Since the waves are traveling in opposite directions, we can consider them as two separate waves with a combined wavelength of 1.6m.

Using the given values, we can solve for the frequency: 250 m/s = f * 1.6m, which gives us f = 156.25 Hz.

Now, to find the number of standing wave segments, we can use the formula n = L/λ, where n is the number of segments, L is the length of the string, and λ is the wavelength. Plugging in the values, we get n = 2.0m / 1.6m = 1.25 segments.

Since we can't have a fractional number of segments, we round down to 1 segment. This means that there is only one standing wave set up in the string.

I hope this helps and good luck with your assignment! Remember, miracles happen when we put in the effort and time to understand and solve problems. Best of luck!