Tangent Plane And Normal Vector.

by dcl
Tags: normal, plane, tangent, vector
dcl is offline
Jun6-04, 01:06 AM
P: 55
I'm having trouble working out the tangent plane of an equation at a specified point (4,1,-2)
The equation being [tex]9x^2 - 4y^2 - 25z^2 = 40[/tex]

[tex]\nabla f = (18x, -8y, -50z)[/tex] yeh?
Just reading off this should give us the normal vector shouldn't it? (18,-8,-50)
and from that we can work out the equation of the plane.
18(x-4) - 8(y-1) -50(z-(-2)) = 0
Is this corrent or am I using a horribly flawed method?
Phys.Org News Partner Science news on Phys.org
SensaBubble: It's a bubble, but not as we know it (w/ video)
The hemihelix: Scientists discover a new shape using rubber bands (w/ video)
Microbes provide insights into evolution of human language
dcl is offline
Jun6-04, 01:33 AM
P: 55
Think I've worked it out for myself.
Method was sorta wrong.
Once I have Grad F, all I need to do is sub in the values of the point and It will give me the normal vector and from that I can work out the equation.
I think thats right.

Register to reply

Related Discussions
Tangent and normal acceleration, curvature radius General Physics 2
Normal to a Tangent Plane of graph F/Gradient of F Calculus & Beyond Homework 0
normal vector of a plane Calculus & Beyond Homework 5
Tangent/normal/area for this Circle.. Differential Geometry 2
Tangent and normal lines Calculus 2