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Tangent Plane And Normal Vector. 
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#1
Jun604, 01:06 AM

P: 55

I'm having trouble working out the tangent plane of an equation at a specified point (4,1,2)
The equation being [tex]9x^2  4y^2  25z^2 = 40[/tex] now [tex]\nabla f = (18x, 8y, 50z)[/tex] yeh? Just reading off this should give us the normal vector shouldn't it? (18,8,50) and from that we can work out the equation of the plane. 18(x4)  8(y1) 50(z(2)) = 0 Is this corrent or am I using a horribly flawed method? 


#2
Jun604, 01:33 AM

P: 55

Think I've worked it out for myself.
Method was sorta wrong. Once I have Grad F, all I need to do is sub in the values of the point and It will give me the normal vector and from that I can work out the equation. I think thats right. 


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