| Thread Closed |
The Expectation of X and the Expectation of X squared (discrete math) |
Share Thread | Thread Tools |
| Mar3-09, 02:05 AM | #1 |
|
|
The Expectation of X and the Expectation of X squared (discrete math)
1. The problem statement, all variables and given/known data
prove or disprove that E[X^2] = E(X)^2 2. Relevant equations E[X] = [tex]\sum[/tex]xi*pr(xi) 3. The attempt at a solution I really don't know where to start, I believe that it is not true, so I should try to disprove it, and the easiest way to do that would be by counterexample... I don't understand expectation very well though, I could try to do a mathematical proof to show that they are not equal, but I don't know how to go about that either. |
| Mar3-09, 02:27 AM | #2 |
|
Recognitions:
|
hi sammC - this is ripe for a counter example...
easiest would be to try a distribution with only 2 outcomes, ie 50% probability of each occurring, then calculate E[x] and E[X^2] note E[X^2] = sum over i of pr(xi)*(xi^2) |
| Mar3-09, 02:53 AM | #3 |
|
|
ah, this helps a bunch, thanks!
|
| Thread Closed |
| Thread Tools | |
Similar Threads for: The Expectation of X and the Expectation of X squared (discrete math)
|
||||
| Thread | Forum | Replies | ||
| Expectation Value | Advanced Physics Homework | 1 | ||
| Expectation value | Advanced Physics Homework | 3 | ||
| Expectation value | Calculus & Beyond Homework | 9 | ||
| conditional expectation (discrete + continuous) | Calculus & Beyond Homework | 3 | ||
| expectation value | Advanced Physics Homework | 4 | ||