# How fast is this roller coaster?

by Bottomsouth
Tags: coaster, roller
 P: 27 1. The problem statement, all variables and given/known data A 350kg roller coaster starts from rest at point A and slides down the frictionless loop-the-loop shown in the accompanying figure. http://session.masteringphysics.com/.../5/1027487.jpg 1. How fast is this roller coaster moving at point B? 2. How hard does it press against the track at point B? 2. Relevant equations 1. it has potential energy at A = mgh =350*9.8*25= 85750 joules at B it has PE = 350*9.8*12=41160 joules the difference has been changed to kinetic energy = 1/2 mv^2 1/2 mv^2 = 1/2 (350)v^2 =85750 - 41160 =16 m/s this is good. 3. The attempt at a solution 2. F = mv^2/R = 350*16^2/6 = 14933.3 It says this isnt the answer.
HW Helper
P: 6,202
 Quote by Bottomsouth 3. The attempt at a solution 2. F = mv^2/R = 350*16^2/6 = 14933.3 It says this isnt the answer.
There is your problem, the centripetal force,mv2/r is the resultant force. Normal reaction acts upwards,the weight acts downwards, the resultant of these two is the centripetal force (which you can calculate and you can also calculate the weight ,mg)
 P: 27 How do I find normal force? n-mg = C_f? n - 350(9.81) = C_f what is n?
HW Helper
P: 6,202
How fast is this roller coaster?

 Quote by Bottomsouth How do I find normal force? n-mg = C_f? n - 350(9.81) = C_f what is n?
Cf is the centripetal force mv^2/r, which you can easily find since you have v at point B, mass,m and the radius r.

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