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universal gravity |
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| Mar10-09, 07:01 PM | #1 |
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universal gravity
1. The problem statement, all variables and given/known data
A sensitive gravimeter is carried to the top of Chicago's Sears Tower, where its reading for the acceleration of gravity is 0.00136 m/s^2 lower than at street level. Find the height of the building. 2. Relevant equations F = GMm/(r^2) and maybe K + U = K_o + U_o 3. The attempt at a solution don't know where to start! |
| Mar10-09, 07:09 PM | #2 |
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consider other units for m/s^2
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| Mar10-09, 07:17 PM | #3 |
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Well I think I could use (g - 0.00136) = g_t.
I dont know how I could use this though. |
| Mar10-09, 07:20 PM | #4 |
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universal gravity
wait could I do this :
(9.8 - 0.00136) = GMm/r^2 ? |
| Mar10-09, 07:27 PM | #5 |
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Recognitions:
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Yes, so you can then write ...
g*r12 = G*M= (g - .00136)*r22 |
| Mar10-09, 07:33 PM | #6 |
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what happened to small m (9.8 - 0.00136)(r^2) = GM (m?) |
| Mar10-09, 07:51 PM | #7 |
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Recognitions:
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m*g*r12 = G*M*m= m*(g - .00136)*r22
If that makes you happier. It isn't a factor. F = m*g = GM*m/r2 g = GM/r2 |
| Mar10-09, 08:01 PM | #8 |
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so,
let G_t = (9.8-0.00136); then, G_t*r^2 = GM M = G_t*r^2 / G and r is the radius of the earth and G is the universal gravity constant. m ~ 9.3579 * 10 ^ 17 But what does this mean? This is the mass of th building and.... |
| Mar10-09, 08:05 PM | #9 |
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Recognitions:
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In case you didn't notice you don't need G and you don't need M and you don't need m.
You just need re and g. Building height will be Δr = r2 - r1 where r1 = re |
| Mar10-09, 08:07 PM | #10 |
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why is that?
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| Mar10-09, 08:12 PM | #11 |
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so
(9.8-0.00136) r^2 = GM and GM is just dropped? why? |
| Mar10-09, 08:15 PM | #12 |
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Recognitions:
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g*r12 = (g - .00136)*r22 You just need re and g. Building height will be Δr = r2 - r1 where r1 = re |
| Mar10-09, 08:20 PM | #13 |
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OK, i guess.
so (9.8-0.00136) ( 6.37 * 10^6)^2 = R1; R1 - R2 = height of tower R1 ~ 3.976 * 10^14 R2 = (6.37 * 10^6) right I got 6.37 * 10^6 as the radius of the earth from my book. |
| Mar10-09, 08:36 PM | #14 |
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Recognitions:
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No.
Try being more careful. (6378)2 km = 40678884 now multiply by 9.81/(9.81 - .00136) = ... then take the square root. Then subtract one from the other. Keep as much precision as you can. Your answer will be less than a km. Multiply by 1000 for meters. |
| Mar10-09, 08:48 PM | #15 |
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(6378)^2 = 40678884
ans * 9.81 / (9.81-0.00136) = 40684524.26 sqrt(ans) = 6378.44 ?? |
| Mar10-09, 08:51 PM | #16 |
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confused even more. Dont know where 6378 came from and why
sqrt ( ans * 9.81/(9.81-0.00136) ) ... ... |
| Mar10-09, 09:10 PM | #17 |
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Recognitions:
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Now 6378.44 - 6378 = .44 km = 440 m = height of building. |
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