How Do I Calculate the Height of a Fence in Projectile Motion?

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SUMMARY

The discussion focuses on calculating the height of a fence in projectile motion, specifically for a golf ball hit at ground level. Given that the acceleration due to gravity (g) is 32 ft/s², the ball reaches its maximum height 8.3 seconds after being hit and clears a fence 1.2 seconds later, located 482 feet away. To find the height of the fence, one must calculate the maximum height of the ball and then determine the distance it falls in 1.2 seconds, subtracting this from the maximum height.

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physics=headache
ok i am so lost as to how to start this problem. the problem goes like this :
assume g = 32ft/s^2
A golf ball is hit at ground level. the ball is observed to reach its maximum height above ground level 8.3 s after being hit. 1.2 s after reaching this maximum height, the ball is observed to barely clear a fence that is 482 ft from where it was hit. How high is the fence? answer in units of ft.

i think the problem I'm having with this problem is figuring out the height of the fence, i know how to figure out the max height, but where do i go from that. i know all the formulas for kinematics in 2 dimensions. i would appreciate any help u can give me.

thanks
 
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482 feet is there just to confuse you (or to give you some information about the horizontal speed of the ball, in case there are more parts to the problem).

As far as the height of the fence is concerned, if you have figured out the maximum height of the ball, just figure out how far the ball falls in 1.2 seconds with initial velocity of 0 (vertical) and subtract that distance from the max. height.
 
thanks for the help

thanks that helped a lot
 

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