Finding Electrical Field Around a Charge

[celect]

Can someone let me know if I'm going in the right direction.

The electrical force on a 2-columb charge is 60 Newtons, What iis the magnitude of the electric field?

E =f/q
E= 60/2
E=30





If a charge of +3 x 10 -6columbs sets up an electrical field, find:

a. The magnitude of the field 9 meters away.

b. The directive of the field.

(I don't know how to set this up)

 

[cookiemonster]

1. Yes.

2. Use Coloumb's Law.

cookiemonster

 

[M98Ranger]

You are on the right track! The equation for electric field is E = F/q, where E is the electric field, F is the force, and q is the charge. So, for the first question, the magnitude of the electric field is 30 N/C (newtons per coulomb).

For the second question, to find the magnitude of the field at a distance of 9 meters, we can use the equation E = kQ/r^2, where k is the Coulomb's constant (9 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance. Plugging in the values, we get E = (9 x 10^9)(3 x 10^-6)/(9)^2 = 1 x 10^3 N/C.

To find the direction of the electric field, we can use the principle that electric field lines always point away from positive charges and towards negative charges. So, in this case, the electric field lines would point away from the +3 x 10^-6 C charge.

I hope this helps! Keep up the good work.