# calculating the magnitude of the force on an electron

by jaa72
Tags: electron, force, magnitude
 P: 1 1. The problem statement, all variables and given/known data an electron travels at a speed of 2.0X10^4 m/s threw a uniform magnetic feild whose magnitude is 1.2x10^4 T. what is the magitude of of the force on the electron if its velocity vector and magnetic vector are a)parralel b)45degrees c)parralel 2. Relevant equations Fmax=QVB F=QVSintheta 3. The attempt at a solution for a i got .0012 b i got 16.47N c i got 0 i think i am using the wrong equations
 HW Helper P: 6,207 well using the right hand rule, which says that the current,force and magnetic field are at 90 degrees to each other, you'd see that if the velocity direction is parallel to the magnetic field you have no force. Use th equation F=BQvsin$\theta$ to get the force for part b

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