Register to reply 
Calculating the magnitude of the force on an electron 
Share this thread: 
#1
Mar2209, 09:33 PM

P: 1

1. The problem statement, all variables and given/known data
an electron travels at a speed of 2.0X10^4 m/s threw a uniform magnetic feild whose magnitude is 1.2x10^4 T. what is the magitude of of the force on the electron if its velocity vector and magnetic vector are a)parralel b)45degrees c)parralel 2. Relevant equations Fmax=QVB F=QVSintheta 3. The attempt at a solution for a i got .0012 b i got 16.47N c i got 0 i think i am using the wrong equations 


#2
Mar2209, 11:22 PM

HW Helper
P: 6,202

well using the right hand rule, which says that the current,force and magnetic field are at 90 degrees to each other, you'd see that if the velocity direction is parallel to the magnetic field you have no force.
Use th equation F=BQvsin[itex]\theta[/itex] to get the force for part b 


Register to reply 
Related Discussions  
Calculating absolute magnitude and apparent magnitude  Advanced Physics Homework  1  
Calculating the magnitude of the net force bewteen charges  Introductory Physics Homework  5  
Magnitude and direction of the force on the electron  Advanced Physics Homework  1  
Electron Sphere and Magnitude  Introductory Physics Homework  7  
Calculating magnitude and direction  Introductory Physics Homework  0 