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Projectile Motion 
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#1
Mar3009, 05:59 PM

P: 26

1. The problem statement, all variables and given/known data
A projectile is launched with a speed of 40 m/s at an angle of 60 degrees above the horizontal. Use conservation of energy to find the maximum height reached by the projectile during its flight. 2. Relevant equations KEi+PEi=KEf+PEf 3. The attempt at a solution i am not sure where vf would come from. Would it be just Vi*cos(60)? I am not sure why that makes sense. Does Vix=Vf?...and why? 


#2
Mar3009, 06:05 PM

HW Helper
P: 5,343

And at the height it has no vertical kinetic energy and the potential energy is what? What is the vertical component of V? (Hint: it's not Vi*cos(60)) 


#3
Mar3009, 06:09 PM

P: 26

why do i need the vertical component of Vi
I dont know how to find the V at the heighest point... At the heighest point is the V in vertical direction 0 anyway? 


#4
Mar3009, 06:20 PM

P: 26

Projectile Motion
I think i solved this out...i got 61m???



#5
Mar3009, 06:49 PM

HW Helper
P: 5,343

But your initial V is the vertical component of V, as that is the component of V that is affected by gravity ... you know, where that potential energy is building. 


#6
Mar3009, 07:26 PM

P: 26

Thank you...can you check if my answer is right?



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