How to find the k constant of a spring?

  • Context: Undergrad 
  • Thread starter Thread starter rss14
  • Start date Start date
  • Tags Tags
    Constant Spring
Click For Summary
SUMMARY

The discussion centers on determining the spring constant (k) of a spring used in a lab experiment where it was launched to hit a target 2.01m away and 0.22m high. The participant calculated the k constant to be 2.752 N/m using the equation Eg + Ee = Eg, considering gravitational potential energy and elastic energy. The spring's length at equilibrium is noted as 0.04m, and the force at a compression of 0.035m is calculated to be 0.09632N. The participant questions whether these values are too small, suggesting potential errors in their method.

PREREQUISITES
  • Understanding of gravitational potential energy (Eg) and elastic potential energy (Ee)
  • Familiarity with the spring constant (k) and Hooke's Law (F = kx)
  • Basic knowledge of projectile motion and angles
  • Ability to perform energy conservation calculations
NEXT STEPS
  • Review the principles of energy conservation in spring systems
  • Learn about the derivation and application of Hooke's Law
  • Investigate methods to experimentally determine the spring constant (k)
  • Explore the effects of angle and height on projectile motion
USEFUL FOR

Students in physics, particularly those studying mechanics and energy conservation, as well as educators looking for practical applications of spring dynamics in experiments.

rss14
Messages
38
Reaction score
0
EDIT: I just found the homework board, mods: don't bother moving this thread, just delete it. Thanks

We had a lab where we launch springs with an unknown k constant to a target 2.01m away and 0.22m high. We also know the angle at which we shot the spring.

We need to find the k constant of the spring, so my question is, does the kinetic energy matter?

Will the equation be:

Eg + Ee = Eg + Ek (The spring had gravitational potential as it was launched a bit higher than the reference position (the table)

or

Eg + Ee = EgThanks.
 
Last edited:
Physics news on Phys.org
If I did the Eg + Ee = Eg method, then my k constant turned out to be 2.752 N/m.

The spring's length at equilibrium is 0.04m; the spring is quite tiny.

Does this k constant seem to small?
 
Also, using F= kx, the force contained in the spring when x = 0.035m, is 0.09632N

Are these values too small, which could possibly hint the method I tried is wrong?
 
Last edited:

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
29
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
Replies
7
Views
1K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K