no idea how to solve this

chhitiz

can somebody please tell me if there is any way to find all values of k for which 6k²+4k is of form 6ab+5a+b? eg. for k=1, 6k²+4k=10=6x0x2+5x2+0

Almutairi

I might have misunderstood the question, but Based on what you made a=2 and b=0. Can you give them any value you want?
In that case can't you always make a=0, b= (6K ² +4k)?
So that 6k²+4k is always of the form 6ab+5a+b, where K is any rational number.
eg. for k=1, 6k²+4k=10=6x0x10+5x0+10
Or should I just go back to my lunch

chhitiz

yeah sorry about that, but a can't be 0. has to be a integer>0. b,though can be >=0