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implementing Hall Effect Sensor |
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| Jun29-09, 12:03 PM | #1 |
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implementing Hall Effect Sensor
Hi, I am working with a solenoid and I am trying to measure the magnetic field that it can produce using a Hall Effect Sensor but I cannot seem to get any results from the sensor. Does anyone know how this is suppose to be done? Thanks.
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| Jun29-09, 12:09 PM | #2 |
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Mentor
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| Jun29-09, 12:33 PM | #3 |
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it is a linear hall effect sensor but I was not able to find out the specific model (the sensor was given to me). I have attached a PDF with the basics of my set up. Is it conceptually correct?
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| Jun29-09, 12:43 PM | #4 |
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implementing Hall Effect Sensor |
| Jun29-09, 02:01 PM | #5 |
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Look at Allegromicro for Hall Effect sensors. Digikey has a few models. See
www.digikey.com http://search.digikey.com/scripts/DkSearch/dksus.dll http://www.allegromicro.com/en/Produ...sors/index.asp These will not work easily unless your solenoid is DC. [Edit] This is one Allegro unit available at Digikey: http://search.digikey.com/scripts/Dk...me=620-1024-ND The magnetic field is perpendicular to flat face. They have 16,545 in stock; $1.74 each. Linear field sensor, 5.25 Gauss per millivolt. You want the 3-SIP or SIP-3 case. What is the maxumum thickness you can use? |
| Jun29-09, 08:34 PM | #6 |
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Recognitions:
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Hall effect sensors have very low output voltages and even the ones that have internal amplifiers are not very sensitive.
Try holding it near a strong permanent magnet at one of the poles and verify that the voltage output changes when you rotate the sensor. You would need a large DC current in a big flat solenoid to get a good deflection without further amplification. Typically, they need a 5 volt power supply and the output is 2.5 volts when they are not in a magnetic field. |
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| electromagnet, electromagneticfield, hall effect, measure |
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