Solve for Man's Velocity on Ice After Throwing Book at 20 m/s

  • Thread starter Thread starter terpsgirl
  • Start date Start date
  • Tags Tags
    Velocity
Click For Summary
SUMMARY

The problem involves calculating the velocity of an 80.0 kg man on a frictionless ice surface after he throws a 4.00 kg book at a velocity of 20.0 m/s. By applying the conservation of linear momentum, the equation M1U1 + M2U2 = M1V1 + M2V2 is utilized. The initial momentum of both the man and the book is zero, leading to the equation 0 = 80V + 80, which simplifies to V = -1 m/s. Thus, the man moves in the opposite direction at a velocity of 1 m/s.

PREREQUISITES
  • Understanding of linear momentum conservation
  • Basic knowledge of mass and velocity calculations
  • Familiarity with the concept of frictionless surfaces
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the principles of conservation of momentum in different systems
  • Explore real-world applications of momentum in sports physics
  • Learn about frictionless motion and its implications in physics
  • Investigate the effects of varying mass and velocity on momentum
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding momentum and motion in frictionless environments.

terpsgirl
Messages
29
Reaction score
0
Velocity question?? Need help..

An 80.0 kg man is standing on a frictionless ice surface when he throws a 4.00 kg book at 20.0 m/s. WIth what velocity does the man move across the ice?


Would I be using Mass= weight/gravity?

Astronaut weight = 80.0 kg
Astronaut v = ? m/s

Book weight= 4.00 kg
Book v= 20.0 m/s
 
Physics news on Phys.org
Are you familiar with the conservation of linear momentum?

- Warren
 
terpsgirl said:
An 80.0 kg man is standing on a frictionless ice surface when he throws a 4.00 kg book at 20.0 m/s. WIth what velocity does the man move across the ice?


Would I be using Mass= weight/gravity?

Astronaut weight = 80.0 kg
Astronaut v = ? m/s

Book weight= 4.00 kg
Book v= 20.0 m/s

Apply the law of linear momentum.
Before the throw: Man mass = 80kg, velocity = 0, Book mass = 4kg, velocity = 0.
After the throw: Man mass = 80kg, velocity = V. Book mass = 4kg, velocity = 20.

M1U1 + M2U2 = M1V1 + M2V2
(80x0) + (4x0) = (80V) + (4x20)
0=80V + 80
80V = -80
V = -80/80
V= -1m/s.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 24 ·
Replies
24
Views
8K
Replies
18
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K