Newton's Second Law and a bathroom scale

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Homework Help Overview

The discussion revolves around a physics problem involving Newton's Second Law, specifically in the context of a bathroom scale used in an elevator. The original poster presents a scenario where the scale measures the force exerted by a teacher in various conditions of elevator motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the readings on the scale under different conditions of elevator motion, questioning the textbook answers. Participants inquire about the methods used to arrive at these answers and suggest examining the calculations for potential errors.

Discussion Status

Participants are actively engaging in verifying the calculations and discussing the assumptions made in the problem. Some suggest that the textbook may contain errors, while others express skepticism about the reliability of the provided answers.

Contextual Notes

There is a noted confusion regarding the interpretation of the elevator's motion, particularly the distinction between constant speed and acceleration. Participants are also considering the implications of using different values for gravitational acceleration in their calculations.

nguyentech
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This question has been troubling me... :

A physics teacher decides to use bathroom scales (calibrated in Newtons) in an elevator. The scales provide a measure of the force with which they push up on the teacher. When the lift is stationary the reading on the bathroom scales is 823 N. What will be the reading on the scales when the elevator is:

a) moving upwards at a constant speed of 2.0 m/s/s
b) accelerating downwards at 2.0 m/s/s
c) accelerating upwards at 2.0 m/s/s

The apparent answers at the back of the textbook read:
a) 700 N
b) 5.6 x 10^2 N
c) 8.4 x 10^2 N

I think they are wrong?

My answers are:
a) 823 N
b) 655 N
c) 991 N

Are my answers correct?
 
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How did you arrive at your answers? That way we can see if you are faulted in your method or not.
 
Yes, place where your work here so we could determine where any potential problem went.
 
For lift accelerating upwards : T = mg + ma, therefore answer = 84*9.8 + 84*2 = 991
For lift accelerating downwards : T = mg - ma, therefore answer =
84*9.8 - 84*2 = 655
 
Ok, well for 1, i assume it said moving at a constant 2 m/s not m/s/s...in that case, you are right, the Normal force(what the scale reads) is the same

Ok, your equation is Fn-Fg=m*a

For 2 m/s^2 upward, you have Fn-823=(823/9.8)*2

Which means Fn=991...which is what u got...

And for downward Fn-823=(823/9.8)*-2 which gives Fn= 655

Either were both making the same mistake (I haven't done these in a while lol) or the book is just wrong..

Lemme try to use g=10 for the calculations..
Fn=987 and Fn=658..yea still close to our answers and far from the books..

I think the fact that they say that with constant speed, the normal force changes, says that the book is broken
 
Yeah, the book is wrong.
 
the book is wrong
 
This is why i never trust books.
 

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