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confused on this dielectric capacitance problem |
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| Jun24-04, 02:12 PM | #1 |
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confused on this dielectric capacitance problem
The electric field between the plates of a paper-separated (K=3.75) capacitor is 9.41E4 V/m. The plates are 1.75mm apart and the charge on each plate is 0.775E-6C. Determine the capacitance of the capacitor and the area of each plate?
I got the voltage by V=Ed. and that came out to 164.675 Where do i go from there because in order to get capacitance you need to know area, and finding the area of each plate is also a question in the problem. I thought about using C=Q/V, but that doesn't apply for dielectrics. Can someone helpme out? |
| Jun24-04, 02:58 PM | #2 |
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I think you should be able to use the fact that [itex]E = \frac{Q}{\epsilon_0A}[/itex]. This gives you an equation for the area which you can use to determine the capacitance.
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| Jun24-04, 03:28 PM | #3 |
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I tried that and that did not work out either, do you have anymore suggestions?
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