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Getting the tension(Static equilibirum) 
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#1
Aug909, 12:40 AM

P: 6

1. The problem statement, all variables and given/known data
A system cord is knotted at point 0. Determine the angle of the force exerted at cord c If the mass of the hanging block is A=850g(8.34N) the tension in B=42N (the angle of Cord B is 25 degrees from the Xaxis) The Image: http://tinypic.com/m/5ani0y/3 2. Relevant equations a/sinA = b/sinB = c/sinC 3. The attempt at a solution 8.43/sinA = 42/sinB = c/sin65 so to get the value of c I need to use the cosine law w/c gives me the answer of c=34.544 If i substitute this value in getting the value of sinA it will be sinA=(34.544)(8.34)/Sin65 w/c gives me a wrong answer. Help please 


#2
Aug909, 01:36 AM

P: 605

How about starting off with the sum of the forces for each component?



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