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Output of the circuit as function of time

by atan691988
Tags: diode, waveform
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atan691988
#1
Aug9-09, 12:02 PM
P: 2
can anyone help me with this>>>

* If the input is Given by Vin = V0 cosωt, plot the output of the circuit as function of time. assume an ideal diode model. *
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fleem
#2
Aug9-09, 12:50 PM
P: 461
I can't see the schematic yet, but the ideal diode model is here:

http://en.wikipedia.org/wiki/Diode_modelling
Redbelly98
#3
Aug9-09, 01:38 PM
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Often, in introductory courses, "ideal diode" means zero forward voltage and zero reverse current.

rootX
#4
Aug9-09, 04:06 PM
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Output of the circuit as function of time

Write V_out in terms of the DC voltage source 2V and v_in.

When V-in* is more negative than -2, diode is on so replace it with short circuit. Else diode is off, replace it with open circuit.

But, does it really matter whether diode is on/off in this circuit?
Redbelly98
#5
Aug9-09, 05:52 PM
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Quote Quote by rootX View Post
But, does it really matter whether diode is on/off in this circuit?
Now that I can see the circuit ... no, you're right it does not affect Vout here.
fleem
#6
Aug9-09, 05:57 PM
P: 461
Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy.

Hint 1: An ideal voltage source is unaffected by the current that is being drawn from it.
Hint 2: Consider V_in and the battery as your "ideal voltage source"

(Sheesh I practically gave you the answer)
Redbelly98
#7
Aug9-09, 08:07 PM
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Quote Quote by fleem View Post
Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy.
It was a "pending admin approval" thing. Eventually an admin approved it.
rootX
#8
Aug9-09, 09:00 PM
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Quote Quote by Redbelly98 View Post
Now that I can see the circuit ... no, you're right it does not affect Vout here.
That was question to the OP because I didn't want to provide him a direct answer
Redbelly98
#9
Aug9-09, 09:08 PM
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Oops.
atan691988
#10
Aug11-09, 12:52 PM
P: 2
hahaha. thanks for all your replies guys.

I've already figure it out..

but really thanks to all :D

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