# Output of the circuit as function of time

by atan691988
Tags: diode, waveform
P: 2
can anyone help me with this>>>

* If the input is Given by Vin = V0 cosωt, plot the output of the circuit as function of time. assume an ideal diode model. *
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 P: 461 I can't see the schematic yet, but the ideal diode model is here: http://en.wikipedia.org/wiki/Diode_modelling
 Mentor P: 12,074 Often, in introductory courses, "ideal diode" means zero forward voltage and zero reverse current.
 P: 1,294 Output of the circuit as function of time Write V_out in terms of the DC voltage source 2V and v_in. When V-in* is more negative than -2, diode is on so replace it with short circuit. Else diode is off, replace it with open circuit. But, does it really matter whether diode is on/off in this circuit?
Mentor
P: 12,074
 Quote by rootX But, does it really matter whether diode is on/off in this circuit?
Now that I can see the circuit ... no, you're right it does not affect Vout here.
 P: 461 Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy. Hint 1: An ideal voltage source is unaffected by the current that is being drawn from it. Hint 2: Consider V_in and the battery as your "ideal voltage source" (Sheesh I practically gave you the answer)
Mentor
P: 12,074
 Quote by fleem Gahh! I didn't look at the graphic because I thought it was one of those "pending admin approval" things. Its a link! This is easy.
It was a "pending admin approval" thing. Eventually an admin approved it.
P: 1,294
 Quote by Redbelly98 Now that I can see the circuit ... no, you're right it does not affect Vout here.
That was question to the OP because I didn't want to provide him a direct answer
 Mentor P: 12,074 Oops.
 P: 2 hahaha. thanks for all your replies guys. I've already figure it out.. but really thanks to all :D <<< mods can close these thread.

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