Calculating Buoyancy: Determining Ice Area to Support 3000lb Car

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SUMMARY

The discussion focuses on calculating the minimum area of a 1-foot thick chunk of ice required to support a 3000 lb car floating on water. The key conclusion is that the ice must displace an amount of water equal to the total weight of the car and the ice itself. The calculation involves converting the weight of the car into kilograms, determining the volume of water displaced, and subsequently calculating the necessary area of the ice to achieve that volume.

PREREQUISITES
  • Understanding of buoyancy principles
  • Knowledge of weight conversion (pounds to kilograms)
  • Basic volume calculations
  • Familiarity with the concept of displacement in fluids
NEXT STEPS
  • Learn about Archimedes' principle and its applications in buoyancy
  • Study weight conversion techniques, specifically from pounds to kilograms
  • Explore volume calculation methods for irregular shapes
  • Investigate the properties of ice and its density compared to water
USEFUL FOR

Students in physics, engineers working on buoyancy-related projects, and anyone interested in understanding the principles of floating objects and fluid displacement.

daisyi
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I'm sure that if I can figure one of these out, then I will be able to understand how to compute all this buoyancy stuff.

Anyways, here is is:

What is the smallest area of a chunk of ice that is 1ft thick that will just support a 3000lb car.
 
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I assume the car is floating on the ice in water? If so, then realize that the smallest piece would be totally submerged: the top of the ice sheet would be even with the water. Thus all of the ice is displacing water. So how much water must this ice displace to support the total weight of the car plus the ice? First find the answer in kg, then find the volume. Then you can find the area of ice that will have that volume. Got it?
 
I figured this one out using the help that you gave me from the last problem. Thanks a ton again :)
 

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