|Sep6-09, 06:49 PM||#1|
Two phase flow
20m straight length horizontal pipe (60 mm internal diameter), steam flows at rate 0.5 kg/s, at midpoint there is a valve in the line. inlet pressure to this section of line is 5 bar (gauge), pressure at end of line is 3 bar (gauge). mass quality of steam is 0.8 and 2 phase flow occurs in the line.
I have calculated the mass flow of liquid and vapor in the line, the frictional pressure drop (N/m2) for the horizontal tube (without valve) using lockart martinelli correlation and also predicted the flow pattern at entry to the valve.
However,the part I am having a problem with is..When calculating the pressure drop across the valve.After calculating the homogeneous parameters and inserting them into the pressure drop equation which is: -dp/dz= [ρ*u *du/dz] + [2*f*ρ*u^2/d] + ρ*g*sinθ
First term in the equation i took equal to zero (no change in velocity assumed), but for the last term (ρ*g*sinθ), do i take theta(θ) as equal to zero as it is a horizontal pipe?
My solution is attached.
Thanks for any help!
|Similar Threads for: Two phase flow|
|Alternator Problems (3 phase and single phase AC Motor)||Engineering, Comp Sci, & Technology Homework||3|
|phase equilibrium with unsteady flow||Advanced Physics Homework||0|
|phase equilibrium in a vessel with unsteady flow||Introductory Physics Homework||0|
|Phase, Phase Difference and Phase Shift||General Physics||6|
|HELP - Derive 2-phase 3-dimesional PD flow equation||Calculus & Beyond Homework||0|