C program - trouble with IF statement

[Math Is Hard]

I feel silly asking this but I can't get my "If" statement to work correctly. This should print "a is NOT equal to b" but it prints "a is equal to b".
Any help? Thanks!

#include <stdio.h>
int main(void)
{
int a = 10;
int b = 15;

if(a == b)
printf("a is equal to b \n");
else
printf("a is NOT equal to b \n");

return 0;
}

 

[AKG]

Try using more brace brackets

#include <stdio.h>
int main(void)
{
int a = 10;
int b = 15;

if(a == b)
{printf("a is equal to b \n");}
else
{printf("a is NOT equal to b \n");}

return 0;
}

 

[robphy]

works for me:

#include <stdio.h>

int main(void)
{
int a = 10;
int b = 15;

if(a == b)
printf("a is equal to b \n");
else
printf("a is NOT equal to b \n");

return 0; 
}


$ gcc _test.c

$ ./a.exe
a is NOT equal to b

 

[e(ho0n3]

Another tip: Make sure you are have a == b and not a = b in the code.

 

[e(ho0n3]

One more thing: Get a debugger. You can see what is happening when you step through the code using a debugger than using any other method.

 

[Math Is Hard]

Another tip: Make sure you are have a == b and not a = b in the code.

I do have double equals. I cut and pasted exactly what I am trying to run.

Thanks.

 

[Math Is Hard]

works for me:

bizarre! I create a new.c file and pasted the code back in and now the logic works fine!
I guess it will remain a mystery!

thanks for running that on your end, robphy.

 

[Math Is Hard]

Try using more brace brackets

I'll keep that in mind - thanks!