Acceleration at its highest point?

In summary, the object has an initial velocity of 26 m/s at 54 degrees above the horizontal axis. Its initial horizontal velocity is 15.3 m/s and vertical velocity is 21.0 m/s. The object reaches a height of 22.6 meters in 2.15 seconds and has a velocity of 15.3 m/s at its highest point. The object's acceleration at its highest point is unknown and cannot be determined with the given information. The time the ball is in the air and the distance it travels when it lands on the court cannot be determined without knowing the object's acceleration. It is important to keep the dimensions separate when using equations for motion.
  • #1
maegenr8
8
0

Homework Statement


I need to find the acceleration of the object at its highest point?? I thought it would be zero, but that is wrong.

-The initial velocity is 26 m/s at 54 degrees above the horizontal axis.
-it's initial horizontal velocity is 15.3 m/s and vertical is 21.0 m/s (is this acceleration?)
-It reaches a height of 22.6 meters
-in 2.15 seconds
-the balls velocity at its highest point is 15.3 m/s

What's the balls acceleration at its highest point?
For how long a time is the ball in the air?
When the ball lands on the court, how far is it from the place where it was hit?

Please explain. I'm not sure which values to use for initial velocity, etc. when I use the formulas.


Homework Equations





The Attempt at a Solution



I thought I should use the velocity-time equation. final velocity=initial velocity + acceleration*time
I did 15.3= 26+ 2.15a but the answer was incorrect.
What am I doing wrong?
 
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  • #2
The main thing you need to do is keep you dimensions separate. Work out the equation for all motion in the x plane. Then work out the equation for all motion in the y plane. Try this out first.
 
  • #3
when working it for the values in the x plane would i just use 15.3 as initial velocity or the 26?
 
  • #4
You would use the 15.3 because that is the x component of the velocity.
 
  • #5
okay, 15.3 is the velocity at the balls highest point. is that because it's vertical velocity at its highest point is zero (because at that instance its not going up or down) but it is still moving horizontally and that's why it's 15.3?
 
  • #6
I'm a bit confused by what you are saying. You are correct that the vertical velocity of the ball at its highest point is zero and that the horizontal velocity at its highest point is 15.3, but you need to be more specific when stating the ball's velocity
 

1. What is acceleration at its highest point?

Acceleration at its highest point refers to the rate of change of velocity at the highest point of a moving object. It is the maximum acceleration that an object experiences during its motion.

2. How is acceleration at its highest point calculated?

Acceleration at its highest point can be calculated by dividing the change in velocity by the change in time. It can also be calculated by using the equation a = vf2 - vi2 / 2d, where a is acceleration, vf is final velocity, vi is initial velocity, and d is the distance traveled.

3. What factors affect acceleration at its highest point?

The factors that affect acceleration at its highest point include the initial velocity of the object, the mass of the object, and any external forces acting on the object such as friction or air resistance.

4. Can acceleration at its highest point be negative?

Yes, acceleration at its highest point can be negative if the object is experiencing deceleration or slowing down at its highest point. This could happen if the object is thrown upwards and is being affected by gravity.

5. Why is acceleration at its highest point important?

Acceleration at its highest point is important because it helps us understand the motion of objects and how they are affected by external forces. It also allows us to predict the behavior of objects at their highest point and make calculations related to their motion.

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