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Question: Resistors connected in parallel/ series 
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#1
Sep2009, 09:20 PM

P: 11

1. The problem statement, all variables and given/known data
1.The equivalent resistance of several resistors connected in parallel is always lower than the smallest valued resistor. A) True B) False 2. The following two circuits are equivalent at terminals AB. A) True B) False 3. For three resistors connected in series, the voltage across each resistor is equal even if the resistors have different values. A) True B) False  For number 1, I guessed True. I'm not sure but my reasoning behind is by KCL and KVL, voltages around a loop and current entering a node is zero at every instant. Again, I'm not sure about this one. For number 2, I guessed False. The cicuit on the left, I used Ohm's law to find its voltage; 50(v). On the other hand, the right circuit doesn't have a resistor at all. So I thought since 50(v) is greater than 0 (v) {the right circuit}, the statement is false, which states two circuits are equivalent. For number 3, I guessed True, because by the definition KVL, the sum of voltages around a loop equals zero. I'm confident about my answer for number 3, but I'm doubtful about 1 and 2. 


#2
Sep2109, 01:08 AM

Sci Advisor
PF Gold
P: 1,783

Note: I'm commenting about your reasoning but not saying any of your answers are wrong...or right. It's not sufficient to guess correctly but to know why which I assume you already appreciate.
Number 1 start with the smallest valued resistor by itself. If you add another in parallel will the total resistance go up or down? Number 2 your reasoning looks good. In number 3 there is no mention of a loop. You have three resistors in series. That means current flowing through any one flows through them all so the currents are equal. How does this relate to the voltages? 


#3
Sep2109, 01:35 AM

P: 11

For 1, the total resistance will go up.
For 2, I checked my textbook, and there is an example that shows a circuit and a equivalent circuit of its original circuit. Turns out, I was wrong. This one is actually True. For 3, that means the total voltage passing through each resistor is equal to the total resistance of the three resistors. R1  R2  R3 3ohms 4ohms 5ohms 3volts 4volts 5volts Therefore, it's false!! 


#4
Sep2109, 03:36 AM

Sci Advisor
PF Gold
P: 1,783

Question: Resistors connected in parallel/ series
Nothing beats a nice concrete example to clarify! 


#5
Sep2109, 09:47 AM

P: 639

About question number 2. You have an ideal current source. The current in terminal A will be 5A, whether there is a resistor in series or not.



#6
Sep2109, 10:45 AM

Sci Advisor
PF Gold
P: 1,783




#7
Sep2109, 11:00 AM

P: 568




#8
Sep2109, 11:17 AM

P: 186

Hi Cathode,
for question 3. For three resistors connected in series, the voltage across each resistor is equal even if the resistors have different values. A) True B) False >>> The answer should be B) False. Different resistor value gives different voltage as the current is the same in series. 


#9
Sep2109, 07:47 PM

P: 11

I'm still not understanding about question 1...



#10
Sep2209, 04:57 AM

P: 639




#11
Sep2209, 04:55 PM

P: 11

is the relationship, the product over sum rule?



#12
Sep2209, 07:52 PM

P: 568

If there are two, then the more general expression R = 1/[(1/R1)+(1/R2)] will also be equal to R1 R1 / R1 + R2. But don't try using the product over the sum if there are three or more resistors. 


#13
Sep2209, 08:24 PM

P: 639

[tex]R_{eq}=\frac{R_1R_2}{R_1+R_2}[/tex] Suppose [tex]R_2[/tex] is the smaller resistor. Divide the numerator and the denominator by [tex]R_1[/tex]. You get: [tex]R_{eq}=\frac{R_2}{1 + R_2/R_1}[/tex]. Since [tex]R_2[/tex] is divided by a quantity greater than 1, the result must be smaller than [tex]R_2[/tex]. You can consider the parallel of three resistors as the parallel of one with the equivalent of the parallel of the other two and so on. 


#14
Sep2209, 09:20 PM

P: 11

ahh now I get it.
Thanks so much for the help, everyeon! 


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